MAKR 2009-04-09 a list zipper. This was briefly discussed on the chat today by RS, kruzalex, and teo. The implementation could be like:
proc lzip {l1 l2} { set res {} foreach x $l1 y $l2 { lappend res $x $y } set res }
would lead to
$ lzip {a b c} {1 2 3} a 1 b 2 c 3
A more generic form is available as [interleave].
JAL 2021-06-06 If you want to zip more than 2 lists together, here is a more complex implementation.
proc lzip {args} { set list_l $args set zip_l [] while {1} { set cur [lmap a_l $list_l { lindex $a_l 0 }] set list_l [lmap a_l $list_l { lrange $a_l 1 end }] if {[join $cur {}] == {}} { break } lappend zip_l $cur } return $zip_l }
For example
# leaving off B3 just to show the behavior when one list doesn't have as many elements as others. lzip {A1 A2 A3} {B1 B2} {C1 C2 C3} => {A1 B1 C1} {A2 B2 C2} {A3 {} C3}
And in this code, if one of the lists runs out of elements, but other list(s) still have elements, we insert an empty element, which I think is the behavior that people would expect. Alternatives might be to terminate the zipping.
I think of zipping lists together as a "rotation by 90 degrees", e.g. translating from lists of rows to lists of columns. To elaborate: if you have a list of rows, where each row is a list of elements, but you instead want a list of columns (of elements) then lzip can do that for you simply.