Version 1 of Degree histograms

Updated 2001-11-13 14:08:44

Richard Suchenwirth - In Graph theory in Tcl, a procedure was given how to compute the degree (the number of neighboring vertices) for a vertex of a graph. A graph can be characterized by his degree sequence, a non-increasing sequence of the degrees of the graph's vertices (see http://web.hamline.edu/~lcopes/SciMathMN/concepts/cdegsq.html ), which may look like

 4,4,3,3,2,2,1,1,1,1

As this is ordered, it can equivalently be expressed as another sequence (for now, call it the "degree histogram")

 h = (g0, g1, ... gm) where gi = card({v e V | g(v) = i})

in other words, the number of vertices of each degree from 0 (singleton vertices) to the maximum degree occurring in that graph. Some examples:

 (above) 0 4 2 2 2
 K5 :   0 0 0 0 0 5
 K3,3 : 0 0 0 6

A 5-legged star is 0 5 0 0 0 1, with the nice property that

 g card(E)=1 and g1 = card(E)

A complete graph, where every vertex is connected with each, like K5 above, satisfies

 gi = card(E) when i=card(E); otherwise 0

A 2-regular graph ("ring") with n vertices has the histogram

 0 0 n 

The number of vertices of the graph can be had by summing the histogram entries:

 |V| = sum(i=0,m) gi

and the number of edges by multiplying the histogram entries with their position in the list, finally dividing by two:

 |E| = sum(i=0,m) i gi/2

What that is good for? I experience with simple graphs that their degree histogram is a kind of "fingerprint", so graphs with same degree histogram are isomorphic. I am told that this is not to be expected to be true for every case. I wonder where the boundary is, i.e. which is the smallest pair of non-isomorphic graphs that share the same fingerprint. I somehow feel that the abstraction of degree histograms can be of use e.g. in determining whether a graph is planar.